n,m=map(int,input().split())
a=list(map(int,input().split()))
s=0
for x in range(n):
print((s+a[x])//m,end=' ')
s=(s+a[x])%m
#include <bits/stdc++.h>
#define ll long long
#define pp pop_back
#define sz size()
#define N 200005
#define ff first
#define ss second
#define pb push_back
using namespace std;
int t, n, a[N], m, s;
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cin >> n >> m;
for(int i = 1; i <= n; i++){
cin >> a[i];
s += a[i];
cout << s / m << ' ';
if(s / m > 0){
s = (s % m);
}
}
}
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