108A - Palindromic Times - CodeForces Solution


implementation strings *1000

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Python Code:

h, m = [int(i) for i in input().split(':')]

h1 = int(h)
m1 = int(m)

m1 += 1
if m1 == 60:
    m1 = 0
    h1 += 1
    if h1 == 24:
        h1 = 0

if m1 == 0:
    m = '00'
elif m1 < 10:
    m = '0' + str(m1)
else:
    m = str(m1)

if h1 == 0:
    h = '00'
elif h1 < 10:
    h = '0' + str(h1)
else:
    h = str(h1) 
    
while h != m[::-1]:
        
    m1 += 1
    if m1 == 60:
        m1 = 0
        h1 += 1
        if h1 == 24:
            h1 = 0

    if m1 == 0:
        m = '00'
    elif m1 < 10:
        m = '0' + str(m1)
    else:
        m = str(m1)

    if h1 == 0:
        h = '00'
    elif h1 < 10:
        h = '0' + str(h1)
    else:
        h = str(h1) 
        

print(h + ':' + m)

C++ Code:

#include <bits/stdc++.h>
using namespace std;

#define FastIO ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)


bool check(int h, int m){
	string hh = to_string(h);
	string mm = to_string(m);
	if(hh.size() < 2)hh = "0" + hh;
	if(mm.size() < 2)mm = "0" + mm;
	reverse(mm.begin(), mm.end());
	if(hh == mm)return 1;
	return 0;
}

string mk(int a){
	string s = to_string(a);
	if(s.size() < 2)s = "0" + s;
	return s;
}

int main() {
	FastIO;
	string s;
	cin >> s;
	string hh = s.substr(0, 2), mm = s.substr(3, 2);
	int h = stoi(hh), m = stoi(mm);
	while(1){
		m++;
		if(m == 60){
			m = 0;
			h++;
		}	
		if(h == 24){
			h = 0;
		}
		if(check(h, m))break;
	}
	cout << mk(h) << ":" << mk(m) << '\n';
	return 0;
}

 					 				    	 			 			 	    	


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