brute force implementation math *800

Please click on ads to support us..

Python Code:

import math
(y, b, r) = map(int, input().split()) 
sum = 0
z = min(y, b, r)
if(z == y):
    x = min(b , r)
    if (x == r and r < y +2):
        sum += 3*x - 3
    elif (z == b):
        sum += 3*z
    else:
        sum += 3*z + 3
elif (z == b):
    if (z == r):
        sum += (3*z)-3
    else:
        sum += 3*z
else:
    sum += (3*z)-3
print(sum)

      

C++ Code:

#include <iostream>

using namespace std;

int main() {
    int y, b, r;
    cin >> y >> b >> r;

    // choose the maximum number of blue ornaments
    b = min(b, y+1);
    b = min(b, r-1);

    // adjust yellow and red ornaments accordingly
    y = b-1;
    r = b+1;

    // calculate the total number of ornaments
    int total = y + b + r;

    cout << total << endl;

    return 0;
}

	 	 	  	  			 		  		  		 	   		


Comments

Submit
0 Comments
More Questions

732B - Cormen --- The Best Friend Of a Man
1369A - FashionabLee
1474B - Different Divisors
1632B - Roof Construction
388A - Fox and Box Accumulation
451A - Game With Sticks
768A - Oath of the Night's Watch
156C - Cipher
545D - Queue
459B - Pashmak and Flowers
1538A - Stone Game
1454C - Sequence Transformation
165B - Burning Midnight Oil
17A - Noldbach problem
1350A - Orac and Factors
1373A - Donut Shops
26A - Almost Prime
1656E - Equal Tree Sums
1656B - Subtract Operation
1656A - Good Pairs
1367A - Short Substrings
87A - Trains
664A - Complicated GCD
1635D - Infinite Set
1462A - Favorite Sequence
1445B - Elimination
1656C - Make Equal With Mod
567A - Lineland Mail
1553A - Digits Sum
1359B - New Theatre Square