1131C - Birthday - CodeForces Solution


binary search greedy sortings *1200

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Python Code:

'''

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'''
import math
n=int(input())
l=list(map(int,input().split()))
l.sort()
ans1=[]
ans2=[]

for i in range(n):
    if i%2==0:
        ans1.append(l[i])
    else:
        ans2.append(l[i])
ans1=ans1+ans2[::-1]
for e in ans1:
    print(e,end=" ")

C++ Code:

#include <bits/stdc++.h>
using namespace std;
int main(){
    int n;
    scanf("%d", &n);
    int l[n];
    for(int i = 0; i < n; i++){
        scanf("%d", l+i);
    }
    sort(l, l+n);
    deque<int> d;
    for(int i = 0; i < n; i++){
        if(i % 2) d.push_back(l[i]);
        else d.push_front(l[i]);
    }
    for(int i = 0; i < n; i++){
        printf("%d ", d[i]);
    }
    printf("\n");
    return 0;
}


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