1138A - Sushi for Two - CodeForces Solution

binary search greedy implementation *900

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Python Code: 

import re
 
input()
l = [*map(len, re.findall(r'1+|2+', input()[::2]))]
print(max(map(min, zip(l, l[1:]))) * 2)

C++ Code: 

#include<iostream>
#include<algorithm>
using namespace std;

const int maxi=1e5+9;
int t[maxi]={0};

int window_search(int len)
{
	int maxx=0;
	int i=1,j=2;
	int num1=0,num2=0;
	int num=0;
	while(j<=len)
	{
		num1=1, num2=0;
		while(t[j]==t[j-1]){
			j++;
			num1++;
			if(j>len) return maxx;
		}
		//j++;
		while(t[j]!=t[i]){
			j++;
			num2++;
			if(j>len){
				num=min(num1,num2);
				num*=2;
				maxx=max(maxx,num);
				return maxx;
			}
		}
		j--;
		num=min(num1,num2);
		num*=2;
		maxx=max(maxx,num);
		i=i+num1;
		j=i+1;
	}
	return maxx;
}

int main()
{
	int n;
	scanf("%d",&n);
	for(int i=1;i<=n;i++){
		scanf("%d",&t[i]);
	}
	int ans=window_search(n);
	printf("%d",ans);
	return 0;
}


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