1146A - Love "A" - CodeForces Solution


implementation strings *800

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Python Code:

inp=input()
a_num=inp.count('a')
if a_num<= len(inp)/2:
  print(a_num+a_num-1)
else:
  print(len(inp))

C++ Code:

#include <bits/stdc++.h>
#define int long long
using namespace std;

int32_t main() {
	// your code goes here
	string s;
	cin>>s;
	int n=s.length();
	int cnta=0;
	for(int i=0;i<n;i++){
	    if(s[i]-'a'==0){
	        cnta++;
	    }
	}

	if(cnta>(n/2)){
	    cout<<n<<'\n';
	}
	else cout<<2*cnta-1<<'\n';
	
	return 0;
}


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