1152A - Neko Finds Grapes - CodeForces Solution

greedy implementation math *800

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Python Code: 

import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline

n, m = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
ca, cb = [0] * 2, [0] * 2
for i in a:
    ca[i % 2] += 1
for i in b:
    cb[i % 2] += 1
ans = 0
for i in range(2):
    ans += min(ca[i], cb[i ^ 1])
print(ans)

C++ Code: 

#include<bits/stdc++.h>
#define ll long long
using namespace std;
int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
       ll n,m,a[100100],b[100100];
       ll ev1=0,ev2=0,od1=0,od2=0,ans=0;
       cin>>n>>m;
       for(int i=0;i<n;i++)
       {
                cin>>a[i];
                if(a[i]%2==0)
                ev1++;
                else
                od1++;
       }
       for(int i=0;i<m;i++)
       {
                cin>>b[i];
                if(b[i]%2==0)
                ev2++;
                else
                od2++;
       }
       ans=min(ev1,od2)+min(od1,ev2);
       cout<<ans<<endl;
       
    return 0;
}


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