1165B - Polycarp Training - CodeForces Solution


data structures greedy sortings *1000

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Python Code:

n=int(input())
l=[int(x) for x in input().split()]
l.sort()
count=1
for i in range(0,len(l)):
    if(l[i]>=count):
        count+=1
print(count-1)

C++ Code:

#include <bits/stdc++.h>

using namespace std;

int main()
{
	#ifndef ONLINE_JUDGE

    freopen("input.text", "r", stdin);

    freopen("outputs.text", "w", stdout);

#endif
    int n;
    cin>>n;
    vector<int> v;
    for(int i=0; i<n; i++){
    	int x;
    	cin>>x;
    	v.push_back(x);
    }
    sort(v.begin(), v.end());
    int day=0;
    for(int i=0; i<n; i++){
    	if(v[i]>day){
    		day++;
    	}
    	else{
    		continue;
    	}
    }
    cout<<day<<endl;
   
    return 0;
}


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