brute force *800

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Python Code:

n = int(input())
d = {1: 'A', 2: 'C', 3: 'B', 0: 'D'}
tt = {1: 4, 3: 3 , 2: 2, 0: 1}
a = 0
h = tt[n % 4]
for i in range(1,3):
    if(tt[(n+i)%4] > h):
        a = i
        h = tt[(n + i)%4]
print(a, d[(n+a)%4])

C++ Code:

#include <iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int x=n%4;
    if(x==1){
        cout<<0<<" "<<"A";
    }
    else if(x==2)
   {
       cout<<1<<" "<<"B";
   }
   else if(x==3){
       cout<<2<<" "<<"A";
   }
   else if(x==0){
       cout<<1<<" "<<"A";
   }
return 0;  
}
		 		  		 	 	 		 	 	        		


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