1242A - Tile Painting - CodeForces Solution


constructive algorithms math number theory *1500

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Python Code:

import copy
import os
import sys
from io import BytesIO, IOBase
from collections import Counter, defaultdict
import math
import heapq
import bisect
import collections
def ceil(a, b):
    return (a + b - 1) // b
BUFSIZE = 8192
inf = float('inf')
class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
get = lambda: sys.stdin.readline().rstrip("\r\n")
MOD = 1000000007
def s():
    return list()
def primefs(n):        primes = {}
    while(n%2 == 0 and n > 0):
        primes[2] = primes.get(2, 0) + 1
        n = n//2
    for i in range(3, int(n**0.5)+2, 2):
        while(n%i == 0 and n > 0):
            primes[i] = primes.get(i, 0) + 1
            n = n//i
    if n > 2:
        primes[n] = primes.get(n, 0) + 1
    return primes
n=int(get())
if n==1:
    print(1)
    exit()
l=list(primefs(n))
if len(l)>=2:
    print(1)
    exit()
print(l[0])













C++ Code:

#include <bits/stdc++.h>
using namespace std;
int main(){
    long long n;
    scanf("%lld", &n);
    long long ans = n;
    long long i = 2;
    for(; i * i <= n; i++){
        if(n % i) continue;
        ans = gcd(ans, i);
        ans = gcd(ans, n / i);
    }
    printf("%lld\n", ans);
    return 0; 
}


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