1291A - Even But Not Even - CodeForces Solution


greedy math strings *900

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Python Code:

def cal(l):
    while l and int(l[-1])%2==0:
        l.pop()
    if not l:
        return -1
    j=len(l)-2
    while j>=0:
        if int(l[j])%2==1:
            break
        j-=1
    if j==-1:
        return -1
    for i in range(j):
        l.pop(0)
    return "".join(l)
for pratyush in range(int(input())):
    n=int(input())
    s=input()
    l=list(s)
    print(cal(l))

C++ Code:

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define eb emplace_back
#define endl '\n'
  
void solve(){
    int n; cin>>n;
    vector<int> v;
    for(int i = 0; i<n; i++){
        char x; cin>>x;
        if((x - '0')%2){
            v.pb((x - '0'));
        }
    }
    if(v.size() <= 1){
        cout<<"-1"<<endl;
    }
    else{
        cout<<v[0]<<v[1]<<endl;
    }
}
  
int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int T; cin>>T;
    while(T--){
        solve();
    }
}


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