129A - Cookies - CodeForces Solution


implementation *900

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Python Code:

t = int(input())
s = [int(i) for i in input().split()]
total = sum(s)
even_count = 0
odd_count = 0
for i in s:
    if i % 2 == 0:
        even_count += 1
    else:
        odd_count += 1
if t % 2 == 0:
    if total % 2 == 0:
        print(t - odd_count)
    else:
        print(odd_count)
else:
    if total % 2 == 0:
        print(even_count)
    else:
        print(odd_count)

C++ Code:

#include<bits/stdc++.h>
using namespace std ;
int main(){
    int n;
    cin>>n;
    int arr[n];
    int odd=0,even=0;
    for (int i = 0; i < n; i++)
    {
        cin>>arr[i];
        if (arr[i]%2==1)
        {
            odd++;
        }
        
    }
    even=n-odd;
    if (odd%2==0)
    {
        cout<<even<<endl;
    }
    else{
        cout<<odd<<endl;
    }
    
}


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