1345A - Puzzle Pieces - CodeForces Solution

math *800

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Python Code: 

for _ in range(int(input())):
    n, m = list(map(int, input().split(' ')))
    if 1 in [n, m] or n == m == 2:
        print('YES')
    else:
        print('NO')

C++ Code: 

#include<bits/stdc++.h>
using namespace std;
int main (){

long long int n,p,k,j,x,y;
int t,a[1000],i;
cin>>t;
for(i=0;i<t;++i){
        cin>>x>>y;
if((x==1)||(y==1)){a[i]=1; }
else if(x==2){if(y<=2){a[i]=1; }else{a[i]=0; } }
else if(y==2){if(x<=2){a[i]=1; }else{a[i]=0; } }
else{a[i]=0; } }
for(i=0;i<t;++i){if(a[i]==1){cout<<"YES"<<endl; }  else{cout<<"NO"<<endl; } }
 }


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