137B - Permutation - CodeForces Solution


greedy *1000

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Python Code:


n = int(input())
a = set(map(int, input().split()))

counter = 0
for i in range(n):
    if i + 1 not in a:
        counter += 1

print(counter)

C++ Code:

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define endl "\n"
#define ff first
#define ss second
#define pb push_back
double pi = 3.14159;
const int N = 105;
void solve() {
  int n;
  cin >> n;
  int a[n + 1], freq[5005] = {0};
  int ans = 0;
  for(int i = 1; i <= n; i++) {
    cin >> a[i];
    freq[a[i]]++;
    if(a[i] > n) {
      ans++;
    }
  }
  for(int i = 1; i <= n; i++) {
    ans += max(freq[i], 1) - 1;
  }
  cout << ans;
}
int32_t main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  // int t;
  // cin>>t;

  // while(t--)
      solve();
}




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