1392B - Omkar and Infinity Clock - CodeForces Solution


implementation math *800

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Python Code:

for _ in range(int(input())):
    n, k = list(map(int, input().split(' ')))
    a = list(map(int, input().split(' ')))
    m = max(a)
    a = [m - i for i in a]
    if k % 2:
        print(*a)
    else:
        m = max(a)
        a = [m - i for i in a]
        print(*a)

C++ Code:

#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
#define ll long long
#define pll pair<ll, ll>
int main()
{
    ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    ll i, t, n, k;
    cin>>t;
    while (t--){
        cin>>n>>k;
        ll a[n+1], mx = LLONG_MIN;
        for (i = 1; i<=n; i++){
            cin>>a[i];
            mx = max(mx, a[i]);
        }
        if (k%2==0){
            ll mn = LLONG_MIN;
            for (i = 1; i<=n; i++){
                a[i] = mx - a[i];
                mn = max(mn, a[i]);
            }
            for (i = 1; i<=n; i++){
                cout<<mn-a[i]<<' ';
            }
        }
        else {
            for (i = 1; i<=n; i++){
                cout<<mx-a[i]<<' ';
            }
        }
        cout<<endl;
    }
}


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