#include <iostream>
#include <cmath>
#include <vector>
using namespace std;
#define DEBUG
bool nonPrimeTable[101005];
int aboveSqrtPrimeList[101005];
int aboveSqrtPrimeCount;
// 1~100000有9592個質數
// 10000-9592 = 408
// 408-
// 可以先對sqrt(100000)=316.227以內的質數用B A來query (65個*2 = 130), sqrt(100000)以外的質數用BBBBBBBA來二分搜
bool inSqrtStrat = true;
int currentQuery = 2;
int tmpQuery = -1;
int n;
int lrange = -1, rrange = -1;
int main() {
cin >> n;
if (n == 1) {
cout << "C 1" << endl;
fflush(stdout);
}
for (int i = 2; i <= sqrt(101000); ++i) {
if (nonPrimeTable[i]) {
continue;
}
for (int j = i+i; j <= 101000; j+=i) {
nonPrimeTable[j] = true;
}
}
for (int i = sqrt(n)+1; i <= n; ++i) {
if (!nonPrimeTable[i]) {
aboveSqrtPrimeList[aboveSqrtPrimeCount++] = i;
}
}
lrange = 0;
rrange = aboveSqrtPrimeCount-1;
// initial query
int currentQuery = 2;
int queryNum;
int answer = 1;
while (true) {
if (currentQuery <= sqrt(n)) {
cout << "B " << currentQuery << endl;
fflush(stdout);
cin >> queryNum;
cout << "A " << currentQuery << endl;
fflush(stdout);
cin >> queryNum;
if (queryNum != 0) {
// 如果已經用B刪掉currentQuery的話 照理來講queryNum應該要都是0
// 如果queryNum不是0代表x是currentQuery的倍數
int tmpQuery = currentQuery;
do {
tmpQuery *= currentQuery;
if (tmpQuery > n) {
break;
}
cout << "B " << tmpQuery << endl;
fflush(stdout);
cin >> queryNum;
cout << "A " << tmpQuery << endl;
fflush(stdout);
cin >> queryNum;
} while (queryNum >= 1);
answer *= (tmpQuery / currentQuery);
}
while (nonPrimeTable[++currentQuery]);
}
// if (answer > sqrt(n)) {
// cout << "C " << answer << endl;
// fflush(stdout);
// break;
// }
if (currentQuery > sqrt(n)) {
if (answer * currentQuery > n) {
cout << "C " << answer << endl;
fflush(stdout);
break;
} else {
if (answer != 1) {
for (int i = n/answer+1; i >= 1; --i) {
if (!nonPrimeTable[i]) {
rrange = i;
break;
}
}
for (int i = lrange; i <= rrange; ++i) {
if (answer * aboveSqrtPrimeList[i] > n) {
cout << "C " << answer << endl;
fflush(stdout);
break;
}
cout << "A " << answer * aboveSqrtPrimeList[i] << endl;
fflush(stdout);
cin >> queryNum;
if (queryNum == 1) {
cout << "C " << answer * aboveSqrtPrimeList[i] << endl;
fflush(stdout);
break;
}
}
break;
}
if (lrange == rrange) {
// test lrange and 1
cout << "B " << aboveSqrtPrimeList[lrange] << endl;
fflush(stdout);
cin >> queryNum;
cout << "A " << aboveSqrtPrimeList[lrange] << endl;
fflush(stdout);
cin >> queryNum;
if (queryNum == 0) {
cout << "C " << answer << endl;
fflush(stdout);
break;
} else {
cout << "C " << answer * aboveSqrtPrimeList[lrange] << endl;
fflush(stdout);
break;
}
}
int mid = (lrange + rrange) / 2;
if (rrange - lrange + 1 == 2) {
// test all
bool foundAns = false;
for (int i = lrange; i <= rrange; ++i) {
cout << "B " << aboveSqrtPrimeList[i] << endl;
fflush(stdout);
cin >> queryNum;
cout << "A " << answer * aboveSqrtPrimeList[i] << endl;
fflush(stdout);
cin >> queryNum;
if (queryNum == 1) {
cout << "C " << answer * aboveSqrtPrimeList[i] << endl;
fflush(stdout);
foundAns = true;
break;
} else {
continue;
}
}
if (!foundAns) {
cout << "C " << answer << endl;
fflush(stdout);
break;
} else {
break;
}
} else {
while (rrange - mid == mid - lrange + 1) {
// 2381 2381
// left possible range after reduce 0, 1
// right possible range
// [5 6] failed
// [5 6 7]
// [5 6 7 8]
mid++;
}
}
for (int i = lrange; i <= mid; ++i) {
cout << "B " << aboveSqrtPrimeList[i] << endl;
fflush(stdout);
cin >> queryNum;
}
cout << "A 1" << endl;
fflush(stdout);
cin >> queryNum;
#ifdef DEBUG
cerr << lrange << " " << mid << " " << aboveSqrtPrimeList[mid] << " " << rrange << endl;
#endif
bool foundAns_loop = false;
if (queryNum == 1 + (rrange - mid)) {
// in the right region
lrange = mid + 1;
} else {
// in the left region
rrange = mid;
for (int i = lrange; i <= rrange; ++i) {
cout << "A " << aboveSqrtPrimeList[i] << endl;
fflush(stdout);
cin >> queryNum;
if (queryNum == 1) {
// in the right region
cout << "C " << answer * aboveSqrtPrimeList[i] << endl;
fflush(stdout);
foundAns_loop = true;
break;
}
}
if (!foundAns_loop) {
cout << "C " << answer << endl;
fflush(stdout);
break;
}
}
if (foundAns_loop) {
break;
}
}
}
}
}
1302. Deepest Leaves Sum | 1209. Remove All Adjacent Duplicates in String II |
994. Rotting Oranges | 983. Minimum Cost For Tickets |
973. K Closest Points to Origin | 969. Pancake Sorting |
967. Numbers With Same Consecutive Differences | 957. Prison Cells After N Days |
946. Validate Stack Sequences | 921. Minimum Add to Make Parentheses Valid |
881. Boats to Save People | 497. Random Point in Non-overlapping Rectangles |
528. Random Pick with Weight | 470. Implement Rand10() Using Rand7() |
866. Prime Palindrome | 1516A - Tit for Tat |
622. Design Circular Queue | 814. Binary Tree Pruning |
791. Custom Sort String | 787. Cheapest Flights Within K Stops |
779. K-th Symbol in Grammar | 701. Insert into a Binary Search Tree |
429. N-ary Tree Level Order Traversal | 739. Daily Temperatures |
647. Palindromic Substrings | 583. Delete Operation for Two Strings |
518. Coin Change 2 | 516. Longest Palindromic Subsequence |
468. Validate IP Address | 450. Delete Node in a BST |