for _ in [0]*int(input()):
n=int(input())
a=[*map(int,input().split())]
b=[*map(int,input().split())]
c=[*map(int,input().split())]
p=[a[0]]
for i in range(1,n):
if p[-1]==a[i]:p.append(b[i])
else:p.append(a[i])
if p[0]==p[-1]:p[-1]=a[-1]
if p[0]==p[-1] or p[-2]==p[-1]:p[-1]=b[-1]
if p[0]==p[-1] or p[-2]==p[-1]:p[-1]=c[-1]
print(*p)
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int t,n;
cin >> t;
while(t--) {
cin >> n;
int a[3][n],prev=0;
for(int i=0; i<3; ++i) for(int j=0; j<n; ++j) cin >> a[i][j];
for(int i=0; i<n; ++i)
for(int j=0; j<3; ++j)
if(a[j][i]!=prev && (i<n-1 || i==n-1 && a[j][i]!=a[0][0])) {
prev=a[j][i];
cout << prev << ' ';
break;
}
cout << '\n';
}
}
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