1426B - Symmetric Matrix - CodeForces Solution

implementation *900

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Python Code: 

for i in range(int(input())):
	n, m = map(int, input().split())
	a = []
	for i in range(n):
		a.append([[int(x) for x in input().split()] for i in range(2)])
	ok = False
	for i in range(n):
		ok |= a[i][0][1] == a[i][1][0]
	ok &= m % 2 == 0
	print("YES" if ok else "NO")

C++ Code: 

#include <bits/stdc++.h>

using namespace std;

int main() {
    int t;
    cin>>t;
    while(t--)
{
    string ans;
    int n,m;
    cin>>n>>m;
    ans="NO";
    bool one=0;
        for(int i=0;i<n;i++){
          int a,b,c,d;
          cin>>a>>b>>c>>d;
          one|=(c==b);
        }
        if((!(m&1)&&one))ans="YES";
        cout<<ans<<endl;
}
  return 0;
}


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