1469A - Regular Bracket Sequence - CodeForces Solution

constructive algorithms greedy *1000

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Python Code: 

t = int(input())
for i in range(t):
    s = input()
    if len(s) % 2 == 0 and s[0] != ')' and s[-1] != '(':
        print('YES')
    else:
        print('NO')


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