1492A - Three swimmers - CodeForces Solution


math *800

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Python Code:

n = int(input())
for i in range(n):    
    p, a, b, c = map(int,input().split())
    a1 = a - ((p-1) % a +1)
    b1 = b - ((p-1) % b +1)
    c1 = c - ((p-1) % c +1)
    print(min(a1,b1,c1))

C++ Code:

#include <iostream>
#include <string>
#include <cmath>
#include <utility>
#include <vector>
#include <deque>
#include <list>
#include <stack>
#include <algorithm>
#include <iterator>
#include <fstream>
#define ll long long
#define stream stringstream
#define bismillah ios::sync_with_stdio(false),cin.tie(nullptr),cout.tie(nullptr);
#define testcase ll t; cin>>t; while(t--)
using namespace std;
int main() {
    bismillah;
    testcase
    {
        ll p,a,b,c; cin >> p >> a >> b >> c;
    a = (p % a == 0 ? 0 : a - (p % a));
    b = (p % b == 0 ? 0 : b - (p % b));
    c = (p % c == 0 ? 0 : c - (p % c));
    ll m = min(a,min(b,c));
    cout << m << endl;
    }
    return 0;
}


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