149A - Business trip - CodeForces Solution


greedy implementation sortings *900

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Python Code:

k = int(input())
a = sorted(list(map(int,input().split())))[::-1]
s = 0
t = 0
l = []
d = []
for i in a:
    s+=i
    d+=[s]
for j in d:
    if k == 0:
        print(0)
        break
    elif j>=k:
        print(d.index(j)+1)
        break
else:
    print(-1)
    

C++ Code:

#include <bits/stdc++.h>

using namespace std;

int main()
{
    long long a,b,c=0,h,d,e,f=0,sum=0,j,cnt=0,flag=0,k=0,x,l,in1,in2,p1,p2,g,w,m=0,n;
    stringstream a1,b1;
    vector<string>v;
    map<string,string>mp;
    cin>>a;
    long long aa[12];
    for(int i=0;i<12;i++)
    {
        cin>>aa[i];
    }
    if(a==0)
    {
        cout<<0<<endl;
    }
    else
    {
        sort(aa,aa+12);
    for(int i=11;i>=0;i--)
    {
        sum=sum+aa[i];
        cnt++;
        if(sum>=a)
        {
            flag=1;
            break;
        }

    }
    if(flag==0)
    {
        cout<<-1<<endl;
    }
    else
        
    {
         cout<<cnt<<endl;
    }
   
    }

}



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