1535B - Array Reodering - CodeForces Solution

brute force greedy math number theory sortings *900

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Python Code: 

import math


i = int(input());
for j in range (0,i):
    count=0
    n = int(input())
    a = list(map(int,input().split()))
    a.sort(reverse=True)
    for y in range (0,n):
        if a[y]%2==0:
            a.insert(0,a.pop(y))
    for k in range (0,n-1):
        for x in range(k+1,n):
            if math.gcd(a[k],2*a[x])>1:
                count+=1
    print(count)

C++ Code: 

#include <bits/stdc++.h>
using namespace std;
#define ll long long
int main(){
int t;cin>>t;
while(t--){
    int n;cin>>n;
    vector<int>vt(n);
    int c=0;
    for(int i=0;i<n;i++){
        cin>>vt[i];
    }
    sort(vt.begin(), vt.end(), [](int x, int y) {
      return x % 2 < y % 2;
    });
    for(int i=0;i<n;i++){
        for(int j=i+1;j<n;j++){
            if(__gcd(vt[i],2*vt[j])>1){
                c++;
            }
        }
    }
    cout << c << endl;
}
return 0;
}


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