implementation math *800

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Python Code:

t=int(input())
for j in range(t):
	input()
	xa,ya=[int(i) for i in input().split()]
	xb,yb=[int(i) for i in input().split()]
	xf,yf=[int(i) for i in input().split()]
	if not ((xa==xb==xf and (ya<yf<yb or ya>yf>yb)) or (ya==yb==yf and (xa<xf<xb or xa>xf>xb))):
		print(abs(xa-xb)+abs(ya-yb))
	else:
		print(abs(xa-xb)+abs(ya-yb)+2)

C++ Code:

#include<bits/stdc++.h>

using namespace std;

void solve()
{
	int xa,ya,xb,yb,fa,fb;
	cin >> xa >> ya >> xb >> yb >> fa >> fb;
	int res=abs(xa-xb)+abs(ya-yb);
	if(xa==xb&&xa==fa)
	{
		 if((ya>fb&&yb<fb)||(ya<fb&&yb>fb)) res+=2;
	}

	if(ya==yb&&yb==fb)
	{
		if((xa>fa&&xb<fa)||(xa<fa&&xb>fa)) res+=2;
	}

	cout << res << endl;
}

int main()
{
	int _;
	cin >> _;
	while(_--)
	{
		solve();
	}
}


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