#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define ppb pop_back
#define pf push_front
#define ppf pop_front
#define nl "\n"
#define all(x) (x).begin(),(x).end()
#define sz(x) (int)((x).size())
#define pii pair<ll, ll>
#define mem1(a) memset(a,-1,sizeof(a))
#define mem0(a) memset(a,0,sizeof(a))
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
const long long INF=1e18;
const int32_t M=1e9+7;
const int32_t MM=998244353;
void run_case(){
int n;
cin >> n;
auto query = [&](int i, int j, int k) {
cout << "? " << i << " " << j << " " << k << endl;
cout << flush;
int res;
cin >> res;
return res;
};
vector<int> extremes;
vector<int> vals(n + 1);
for(int i = 3; i <= n; ++i) {
vals[i] = query(1, 2, i);
}
int ind = max_element(all(vals)) - vals.begin();
// ops-performed => n - 2
// one extreme lies in {1, 2, ind}
int xtra = ind == 3 ? 4 : 3;
int fre = count(all(vals), vals[ind]);
if(fre == n - 2) {
if(query(2, 3, 4) < vals[ind]) {
cout << "! 1 2" << endl;
cout.flush();
return;
}
}
fill(all(vals), 0);
for(int i = 2; i <= n; ++i)
if(i != ind)
vals[i] = query(1, ind, i);
int mx = max_element(all(vals)) - vals.begin();
fre = count(all(vals), vals[mx]);
extremes.pb(ind);
if(fre == n - 2)
extremes.pb(1);
else
extremes.pb(mx);
cout << "! " << extremes[0] << " " << extremes[1] << endl;
cout.flush();
return;
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
int tests;
cin >> tests;
while(tests--){
run_case();
cout.flush();
}
}
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129. Sum Root to Leaf Numbers | 120. Triangle |
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75. Sort Colors | 74. Search a 2D Matrix |
71. Simplify Path | 62. Unique Paths |
50. Pow(x, n) | 43. Multiply Strings |
34. Find First and Last Position of Element in Sorted Array | 33. Search in Rotated Sorted Array |
17. Letter Combinations of a Phone Number | 5. Longest Palindromic Substring |
3. Longest Substring Without Repeating Characters | 1312. Minimum Insertion Steps to Make a String Palindrome |