1680A - Minimums and Maximums - CodeForces Solution


brute force math *800

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Python Code:

t = int(input())
for j in range(t):
    l1,r1,l2,r2 = map(int,input().split(' '))
    if(l1<=l2<=r1):
        print(l2)
    elif(l2<=l1<=r2):
        print(l1)
    else:
        print(l1+l2)
        
        

C++ Code:

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N=2e5+10;
void cf()
{
	ll l1,r1,l2,r2;
	cin>>l1>>r1>>l2>>r2;
	if(l2>r1||r2<l1||l1>r2||r1<l2)cout<<l1+l2<<endl;
	else
	{
		cout<<max(l1,l2)<<endl;
	}
}
int main()
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	ll t;
	cin>>t;
	while(t--)
	{
		cf();
	}
}


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