for _ in range(int(input())):
n,s = map(int,input().split())
a=list(map(int,input().split()))
if s>sum(a):
print(-1)
else:
ans=0
i=0
j=0
curr=0
while j<n:
curr+=a[j]
if curr<s:
j+=1
elif curr==s:
ans=max(ans,j-i+1)
j+=1
else:
while curr>s:
curr-=a[i]
i+=1
if curr==s:
ans=max(ans,j-i+1)
j+=1
print(n-ans)
#include<iostream>
#include<stdio.h>
#include<vector>
using namespace std;
#include<algorithm>
#include<cmath>
#include<unordered_set>
#include<unordered_map>
#include<numeric>
#include<queue>
#define endl '\n'
#include<stack>
#include<sstream>
#include<map>
#include<bitset>
#include<cstring>
#include<deque>
#include<set>
#define EPS 1e-6
#define SQU(x) ((x)*(x))
typedef long long ll;
string pre(int time,int add){
string ans;
time+=add;
int h=time/60;
h%=24;
if(h<10)ans+='0';
ans+=to_string(h);
int m=time%60;
if(m<10)ans+='0';
ans+=to_string(m);
return ans;
}
bool check(string s){
if(s[0]!=s[3])return 0;
if(s[1]!=s[2])return 0;
return 1;
}
inline void solve(){
int n,s;
cin>>n>>s;
vector<int>a(n);
for(int i=0;i<n;i++)cin>>a[i];
int l=0,r=0;
int ans=-1;
int sum=0;
while(l<n){
while(sum<=s&&r<n){
sum+=a[r];
if(sum==s){
ans=ans==-1?n-(r-l+1):min(ans,n-(r-l+1));
}
else if(sum>s){
sum-=a[r];
break;
}
r++;
}
sum-=a[l];
l++;
}
cout<<ans<<endl;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t;
cin>>t;
while(t--)solve();
return 0;
}
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