1699A - The Third Three Number Problem - CodeForces Solution

constructive algorithms math *800

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Python Code: 

for _  in range(int(input())):
   n=int(input())
   if n%2==0:
      print(n//2,0,0)
   else:
      print(-1)

C++ Code: 

#include<bits/stdc++.h>

using namespace std;

void testcase(){
    int n;
    cin>>n;

    if(n%2==0)
        cout<<"0 "<<n/2<<' '<<n/2<<'\n';
    else
        cout<<"-1\n";
}
int main()
{
    ios_base::sync_with_stdio(false); cin.tie(0);
    int t;
    cin>>t;
    while(t--)
        testcase();
    return 0;
}


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