n = list(input())
s = input()
f = [0]*10
for i in s:
f[ord(i)-48] +=1
j = 9
i = 0
while(i<len(n) and j>=0):
while j>=0 and f[j]==0:
j -= 1
if ord(n[i])-48 < j:
n[i] = j
f[j]-=1
i+=1
for i in n:
print(i,end="")
#include <bits/stdc++.h>
using namespace std;
#define ll long long int
#define vi vector<int>
#define pii pair<int,int>
#define vii vector<pii>
#define rep(i,a,b) for(int i=a; i<b; i++)
#define ff first
#define ss second
const ll M = 1e9+7;
const ll mm = 998244353;
int main () {
ios_base::sync_with_stdio(false);
cin.tie(NULL); cout.tie(NULL);
string n,m;
cin >> n >> m;
vector<char> v;
for(auto x: m){
v.push_back(x);
}
sort(v.begin(), v.end());
int temp = v.size()-1;
for(int i=0; i<n.length(); i++){
if(n[i] < v[temp]) {
n[i] = v[temp];
temp--;
if(temp < 0) break;
}
}
cout << n << "\n";
return 0;
}
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1401D - Maximum Distributed Tree | 1716C - Robot in a Hallway |
1688B - Patchouli's Magical Talisman | 99A - Help Far Away Kingdom |
622B - The Time | 1688C - Manipulating History |
1169D - Good Triple | 1675B - Make It Increasing |
588A - Duff and Meat | 1541B - Pleasant Pairs |
1626B - Minor Reduction | 1680A - Minimums and Maximums |
1713A - Traveling Salesman Problem | 1713B - Optimal Reduction |
1710A - Color the Picture | 1686B - Odd Subarrays |
251A - Points on Line | 427C - Checkposts |
1159A - A pile of stones | 508A - Pasha and Pixels |
912A - Tricky Alchemy | 1249A - Yet Another Dividing into Teams |
1713C - Build Permutation | 1699A - The Third Three Number Problem |
1617B - GCD Problem | 841A - Generous Kefa |
1690B - Array Decrements | 1692C - Where's the Bishop |