1702A - Round Down the Price - CodeForces Solution

constructive algorithms *800

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Python Code: 

def f(m):
    k = 0

    while 10 ** k <= m:
        k += 1

    return k - 1

t = int(input())

ans = []

for i in range(t):
    m = int(input())

    ans.append(m - 10 ** f(m))


for i in ans:
    print(i)

C++ Code: 

#include <bits/stdc++.h>
using namespace std;
long long int count(long long int n){
    int cnt=0;
    while(n>0){
        cnt++;
        n=n/10;
    }
    return cnt;
}

int main() {
  long long int t;
   cin>>t;
   while(t--){
       long long int n;
       cin>>n;
     long long  int a=count(n);
     long long int h=pow(10,a-1);
       cout<<n-h<<endl;
   }
}


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