t = int(input())
for _ in range(t):
n,a,b = map(int,input().split())
if a+b<=n-2 or (a==b and a==n):
print("Yes")
else:
print("No")
#include <bits/stdc++.h>
using namespace std;
#define ll long long int
ll sol()
{
ll n,a,b;
cin>>n>>a>>b;
if(a==b && n==b)
{
cout<<"Yes"<<endl;
return 0;
}
else
{
if(n-a-b>1)
{
cout<<"Yes"<<endl;
return 0;
}
else{
cout<<"No"<<endl;
return 0;
}
}
return 0;
}
int main()
{
ll t;
cin>>t;
while(t--)
{
ll a=sol();
}
}
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