list = [[],
[],
[]]
n = int(input())
count = 0
for i in range(n):
c = 0
a = input().split()
for j in range(len(a)):
a[j] = int(a[j])
for j in range(3):
list[j].append(a[j])
if list[j][i] == 1:
c += 1
if c > 1:
count += 1
print(count)
#include <iostream>
using namespace std;
int main(){
int n=0,y=0;
cin>>n;
int x[n][3];
for(int i=0;i<n;i++){
for(int j=0;j<3;j++){
cin>>x[i][j];}}
for(int i=0;i<n;i++){
if ((x[i][0]==1&&x[i][1]==1)||(x[i][0]==1&&x[i][2]==1)||(x[i][1]==1&&x[i][2]==1))
y+=1;
}
cout<<y;
return 0;
}Cyclic shifts | Zoos |
Build a graph | Almost correct bracket sequence |
Count of integers | Differences of the permutations |
Doctor's Secret | Back to School |
I am Easy | Teddy and Tweety |
Partitioning binary strings | Special sets |
Smallest chosen word | Going to office |
Color the boxes | Missing numbers |
Maximum sum | 13 Reasons Why |
Friend's Relationship | Health of a person |
Divisibility | A. Movement |
Numbers in a matrix | Sequences |
Split houses | Divisible |
Three primes | Coprimes |
Cost of balloons | One String No Trouble |