276A - Lunch Rush - CodeForces Solution

implementation *900

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Python Code: 

n,k=[int(x) for x in input().split()]
e=0
l=[]
for i in range(n):
    a,b=[int(x) for x in input().split()]
    if b>k:
        e=a-(b-k)
    else:
        e=a
    l.append(e)
print(max(l))

C++ Code: 

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
int main()
{
   ll n,k,i=0,marc;
   cin>>n>>k;
   while(i<n)
   {
       ll a,b;
       cin>>a>>b;
       if(i==0)
       {
           if(b>k)  marc=a-(b-k);
           else     marc=a;
       }
       else{
            ll joya;
            if(b>k)  joya=a-(b-k);
           else     joya=a;
           if(joya>marc)marc=joya;
       }
       i++;
   }
   cout<<marc<<"\n";
}


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