285A - Slightly Decreasing Permutations - CodeForces Solution

greedy implementation *1100

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Python Code: 

n, k = list(map(int, input().split()))

result = [0] * n
index = 0

for v in range(k + 1, n + 1):
    result[index] = f'{v}'
    index += 1
    
for v in range(k, 0, -1):
    result[index] = f'{v}'
    index += 1

print(' '.join(result))

C++ Code: 

#include<bits/stdc++.h>
using namespace std;
 
int main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);cout.tie(0);

    int n, k;
    cin >> n >> k;
    for(int i=0; i<k; i++) cout << n-i << " ";
    for(int i=1; i<=n-k; i++) cout << i << " ";
    cout << '\n';
}


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