brute force implementation *1100

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Python Code:

import math
num,k = list(map(int, input().split(' ')))
count = 0
for i in (range(num)):
         rang = list(map(int, input().split(' ')))
         count += rang[1]-rang[0]+1

count = k* math.ceil(count/k) - count
print(count)

C++ Code:

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include<cmath> //float result = pow(b,p)  //trunc(10.25)=10       // floor(10.55)=10  // ceil(10.55)=11  //round(10.1)=10 , round(10.55)=11
#include <unordered_map> // unordered_map<int,int>mp;
using namespace std;

#define fast                    \
  ios_base::sync_with_stdio(0); \
  cin.tie(0);                   \
  cout.tie(0);

// -842150451
// a=97 , z= 122 , A=65 ,Z=90

#include<set>
int main() {
	//extern  int arr [5]  ;
	//fast	
	int before=0 , after =0 ;
	int n, k; cin >> n >> k;

	for (int i = 0;i<n;i++) {
		int l; cin >> l;
		int r; cin >> r;    
		before += 1 + r - l;
	}
	
	for (int i = 0; true; i++) {

		if ((after+before) % k == 0) {
			break;
		}
			after++;
		
	}

		cout << after << endl;
		
}


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