300A - Array - CodeForces Solution


brute force constructive algorithms implementation *1100

Please click on ads to support us..

Python Code:

n=int(input())
a=list(map(int,input().split()))
a1,a2,a3=[],[],[]
for i in a:
    if i<0:a1.append(i)
    elif i>0:a2.append(i)
    else:a3.append(i)
if not len(a1)&1:
    a3.append(a1.pop())
if len(a2)==0:
    a2.append(a1.pop())
    a2.append(a1.pop())
print(len(a1),*a1)
print(len(a2),*a2)
print(len(a3),*a3)


Comments

Submit
0 Comments
More Questions

168B - Wizards and Minimal Spell
7A - Kalevitch and Chess
912B - New Year's Eve
1537C - Challenging Cliffs
879B - Table Tennis
1674E - Breaking the Wall
1282A - Temporarily unavailable
1366C - Palindromic Paths
336A - Vasily the Bear and Triangle
926A - 2-3-numbers
276D - Little Girl and Maximum XOR
1253C - Sweets Eating
1047A - Little C Loves 3 I
758D - Ability To Convert
733A - Grasshopper And the String
216A - Tiling with Hexagons
1351B - Square
1225A - Forgetting Things
1717A - Madoka and Strange Thoughts
1717B - Madoka and Underground Competitions
61B - Hard Work
959B - Mahmoud and Ehab and the message
802G - Fake News (easy)
1717C - Madoka and Formal Statement
420A - Start Up
1031A - Golden Plate
1559C - Mocha and Hiking
427B - Prison Transfer
330A - Cakeminator
426A - Sereja and Mugs