32A - Reconnaissance - CodeForces Solution


brute force *800

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Python Code:

n,d=map(int,input().split())
A=list(map(int,input().split()))

ANS=0
for i in range(n):
    a=A[i]
    for j in range(n):
        if i==j:
            continue
        if abs(A[j]-a)<=d:
            ANS+=1

print(ANS)

C++ Code:

//
#include <iostream>

using namespace std;

int main() {
	int n, d;
	cin >> n >> d;
	int a[1000];
	for (int i = 0; i < n; i++) {
		cin >> a[i];
	}
	int ans = 0;
	for (int i = 0; i < n; i++) {
		for (int j = i + 1; j < n; j++) {
			if (abs(a[i] - a[j]) <= d) {
				ans++;
			}
		}
	}
	cout << ans * 2;
}


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