33A - What is for dinner - CodeForces Solution

greedy implementation *1200

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Python Code: 

n,m,k=map(int,input().split())
X=[1<<30]*m
for i in range(n):
    a,b=map(int,input().split())
    X[a-1]=min(X[a-1],b)

print(min(sum(X),k))

C++ Code: 

#include <cstdio>

int main(){

    long n(0), m(0), k(0); scanf("%ld %ld %ld", &n, &m, &k);
    long *viability = new long[m + 1];

    const long maxV = 1000000;
    for(long row = 1; row <= m; row++){viability[row] = maxV;}

    for(int p = 0; p < n; p++){
        long currentRow(0), currentV(0); scanf("%ld %ld", &currentRow, &currentV);
        if(currentV < viability[currentRow]){viability[currentRow] = currentV;}
    }

    long total(0);
    for(long row = 1; row <= m; row++){total += viability[row];}
    printf("%ld\n", total < k ? total : k);




    delete[] viability;
    return 0;
}


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