359A - Table - CodeForces Solution


constructive algorithms greedy implementation *1000

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Python Code:

n, m = [int(i) for i in input().split()]

m = []

for i in range(n):
	m.append(input())

for i in range(n):
	if m[i][0] == '1' or m[i][-1] == '1':
		if i == 0 or i == n-1:
			print(1)
		else:
			print(2)
		exit()
	if '1' in m[i] and (i == 0 or i == n-1):
		print(2)
		exit()

print(4)

C++ Code:

// sai_mun

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define Pis pair<int, string>
#define Pi pair<int, int>
#define Pl pair<ll>
#define rep0(i, n) for (__typeof(n) i = 0; i < (n); i++)
#define rep1(i, n) for (__typeof(n) i = 1; i <= (n); i++)
#define push_back pb
const int INF = 1e9;
const ll INFll = 1e18;
const int MAX = 1e5 + 5;
typedef map<int, int> mii;
typedef map<char, int> mci;
typedef map<string, int> msi;

// freopen("input.txt", "r", stdin);
// freopen("output.txt", "w", stdout);
    
int main()
{
     int n,m,a,ans=0; cin>>n>>m;
     rep1(i,n){
        rep1(j,m){
            cin>>a;
            if(a){
                if(i==1 || j==1 || i==n || j==m)ans=2;
            }
        }
     }
     if(!ans)cout<<4<<endl;
     else cout<<ans<<endl;
}


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