390A - Inna and Alarm Clock - CodeForces Solution

implementation

Please click on ads to support us..

Python Code: 







if __name__ == '__main__':
    numAlarmClocks = int(input())
    xDict = {}
    yDict = {}
    for i in range(numAlarmClocks):
        xPos, yPos = input().split(" ")
        if xPos in xDict:
            xDict[xPos] += 1
        else:
            xDict[xPos] = 1
        if yPos in yDict:
            yDict[yPos] += 1
        else:
            yDict[yPos] = 1

    print(min(len(xDict), len(yDict)))

C++ Code: 

#include<bits/stdc++.h>
#define ll long long
using namespace std;

int main()
{
   int n,mx=INT_MIN;
   cin>>n;
   set<int>s1,s2;
   for(int i=0;i<n;i++)
   {
       int a,b;
       cin>>a>>b;
       s1.insert(a);
       s2.insert(b);
   }
    cout<<min(s1.size(),s2.size());
    return 0;
}


Comments

Submit
0 Comments
More Questions

282A - Bit++
69A - Young Physicist
1651A - Playoff
734A - Anton and Danik
1300B - Assigning to Classes
1647A - Madoka and Math Dad
710A - King Moves
1131A - Sea Battle
118A - String Task
236A - Boy or Girl
271A - Beautiful Year
520B - Two Buttons
231A - Team
479C - Exams
1030A - In Search of an Easy Problem
158A - Next Round
71A - Way Too Long Words
160A - Twins
1A - Theatre Square
1614B - Divan and a New Project
791A - Bear and Big Brother
1452A - Robot Program
344A - Magnets
96A - Football
702B - Powers of Two
1036A - Function Height
443A - Anton and Letters
1478B - Nezzar and Lucky Number
228A - Is your horseshoe on the other hoof
122A - Lucky Division