411A - Password Check - CodeForces Solution


*special problem implementation *800

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Python Code:

s = input()
print("Correct" if len(s) >= 5 and any(list(map(lambda x: x in '0123456789',list(s)))) and any(list(map(lambda x: x.isupper(),list(s)))) and any(list(map(lambda x: x.islower(),list(s)))) else "Too weak")

C++ Code:

//ifstream fin("INPUT.TXT");
//ofstream fout("OUTPUT.TXT");
//fin.close();
//fout.close();
//cout << fixed << setprecision(6);
#include<bits/stdc++.h>
#define ll long long
#define ld long double
#define ICC ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define str string
#define pb push_back
#define ull unsigned long long
using namespace std;
void NOK(){
    ull n, m;
    cin >> n >> m;
    cout << (n * m) / __gcd(n, m);
}
void b(){
    str s;
    cin >> s;
    if(s.size() < 5){
        cout << "Too weak\n";
        return;
    }
    bool ok = false, ok1 = false, ok2 = false;
    for(int i = 0; i < s.size(); i ++){
        if(s[i]>='A' and s[i]<='Z'){
            ok = true;
        }
        else if(s[i]>='a' and s[i]<='z'){
            ok1 = true;
        }
        else if(s[i]>='0' and s[i]<='9'){
            ok2 = true;
        }
    }
    if(ok == true and ok1 == true and ok2 == true){
        cout << "Correct\n";
    }
    else{
        cout << "Too weak\n";
    }
}
int main(){
    ICC
    ld t = 1;
    ///cin >> t;
    while(t --){
        b();
    }
} 


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