43A - Football - CodeForces Solution


strings *1000

Please click on ads to support us..

Python Code:

n = int(input())
d = []
for i in range(n):
     a = input()
     d+=[a]
s = 0
w = 0
t = [ ]
for j in d:
     t+=[d.index(j)]
for k in t:
     if k == 0:
          s+=1
     elif k > 0:
          w +=1
if s > w:
      l = t.index(0)
      print(d[l])
elif w > s:
      v = t.index(max(t))
      print(d[v])
          
          


Comments

Submit
0 Comments
More Questions

1486A - Shifting Stacks
1389B - Array Walk
71B - Progress Bar
701A - Cards
545A - Toy Cars
1538E - Funny Substrings
234A - Lefthanders and Righthanders
1611D - Weights Assignment For Tree Edges
197A - Plate Game
1474A - Puzzle From the Future
6B - President's Office
1405B - Array Cancellation
431C - k-Tree
101A - Homework
1642C - Great Sequence
1523B - Lord of the Values
1406C - Link Cut Centroids
2409. Count Days Spent Together
2410. Maximum Matching of Players With Trainers
1604C - Di-visible Confusion
997A - Convert to Ones
218A - Mountain Scenery
486B - OR in Matrix
1405A - Permutation Forgery
1733A - Consecutive Sum
1733B - Rule of League
1733C - Parity Shuffle Sorting
1264A - Beautiful Regional Contest
1695A - Subrectangle Guess
467B - Fedor and New Game