452A - Eevee - CodeForces Solution

brute force implementation strings *1000

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Python Code: 

n=int(input())
x=["jolteon", "flareon", "umbreon", "leafeon", "glaceon", "sylveon"]
mm=input()
if n==6:
    print("espeon")
elif n==8:
    print("vaporeon")
else:
    for i in range(len(x)):
        ff=1
        for j in range(len(x[i])):
            if mm[j]!='.' and x[i][j]!=mm[j]:
                ff=0
                break
        if ff==1:
            print(x[i])
            break

C++ Code: 

#include <bits/stdc++.h>
using namespace std;
int main(){
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int n;
    string s,ss;
    cin >> n >> s;
    string a[8]={"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"};
    for(int i=0;i<8;i++){
        ss=s;
        for(int j=0;j<n;j++){
            if(ss[j]=='.'){
                ss[j]=a[i][j];
            }
        }
        if(ss==a[i]){
            cout << a[i];
            return 0;
        }
    }
    return 0;
}


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