n, m, a, b = list(map(int, input().split()))
if b >= m*a:
print(n*a)
else:
print(min((n//m)*b + n % m*a, ((n+m-1)//m)*b))
#include<bits/stdc++.h>
using namespace std;
#define ll long long
void solve(){
int n,m,a,b;
cin>>n>>m>>a>>b;
int div=b/m;
int rem=b%m;
if(div>=a){
cout<<n*a<<endl;
}
else if(div<a){
int ans=b*(n/m)+min((n%m)*a,b);
cout<<ans<<endl;
}
}
int main(){
int t=1;
// cin>>t;
while(t--){
solve();
}
}
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