496B - Secret Combination - CodeForces Solution

brute force constructive algorithms implementation *1500

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Python Code: 

n=int(input())
num=input()

def right_shift(nb):
    nb=nb[n-1]+nb[:n-1]
    return nb

def add(s1,a):
    nb=''
    for i in range(n):
        nb+=str((int(s1[i])+a)%10)
    return nb

minS=num
for i in range(n):
    diff=10-int(num[0])
    num=add(num,diff)
    if(minS>num):
            minS=num
    num=add(num,10-diff)
    num=right_shift(num)
    if(minS>num):
        minS=num
print(minS)

C++ Code: 

#include <iostream>

using namespace std;
  
int main(){
    int n;
	string s;
	cin >> n >> s;
    string b = s;

    for(int i = 0; i < 10; i++){
		for(int j = 0; j < n; j++)
            s[j] = (s[j] - '0' + 1) % 10 + '0';
        for(int j = 0;j < n; j++)	
			b = min(b , (s+s).substr(j , n));
	}
    cout << b;
    
    return 0;
}/*1698360782.0175083*/


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