4A - Watermelon - CodeForces Solution

brute force math *800

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Python Code: 

n=int(input())
if(n%2==0 and n>2):
    print("YES")
else:
    print("NO")

C++ Code: 

#include <iostream>
using namespace std;

int main()
{
	int x;
	//cout << " enter number : " << endl;
	cin >> x;
	if (x % 2 == 0 && x != 2)
		cout << "Yes" << endl;
	else
		cout << "No" << endl;
}


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