n = int(input())
k1 = list(map(int, input()))
k2 = list(map(int, input()))
print(sum(min(10 - abs(k1[i] - k2[i]),
abs(k1[i] - k2[i])) for i in range(n)))
#include <bits/stdc++.h>
#include <string>
using namespace std;
int main(){
int n;
string s1, s2;
cin>>n>>s1>>s2;
int answer = 0;
for(int i=0; i<n; i++){
int i1 = (int)s1[i] - 48, i2 = (int)s2[i] - 48;
answer += min(abs(i1 - i2), abs(max(i1, i2) - 10) + min(i1, i2));
}
cout<<answer<<endl;
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