598A - Tricky Sum - CodeForces Solution


math *900

Please click on ads to support us..

Python Code:

t = int(input(""))

for i in range(t):
    n = int(input(""))

    sum_pos = n*(n+1)//2

    sum2=1

    while(sum2<=n):
        sum_pos -= 2*sum2
        sum2 *=2

    print(int(sum_pos))

'''
'''


Comments

Submit
0 Comments
More Questions

1472B - Fair Division
1281C - Cut and Paste
141A - Amusing Joke
112A - Petya and Strings
677A - Vanya and Fence
1621A - Stable Arrangement of Rooks
472A - Design Tutorial Learn from Math
1368A - C+=
450A - Jzzhu and Children
546A - Soldier and Bananas
32B - Borze
1651B - Prove Him Wrong
381A - Sereja and Dima
41A - Translation
1559A - Mocha and Math
832A - Sasha and Sticks
292B - Network Topology
1339A - Filling Diamonds
910A - The Way to Home
617A - Elephant
48A - Rock-paper-scissors
294A - Shaass and Oskols
1213A - Chips Moving
490A - Team Olympiad
233A - Perfect Permutation
1360A - Minimal Square
467A - George and Accommodation
893C - Rumor
227B - Effective Approach
1534B - Histogram Ugliness