609A - Флеш-карты - CodeForces Solution


greedy implementation sortings *800

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Python Code:

def _input(): return map(int, input().split())

n = int(input())
m = int(input())
lst = sorted([ int(input()) for _ in range(n)]); res= 0
i=n-1
while i>=0:
    res+=lst[i]
    if res>=m: break
    i-=1
print(n-i)




        

C++ Code:

#include<bits/stdc++.h>
using namespace std;

int main() {
  long long int n,m,x,usb=0;
  cin>>n>>m;

  vector<long long int> v;
  for(long long int i=0; i<n; i++){
    cin>>x;
    v.push_back(x);
  }

  sort(v.begin(), v.end());

  for(long long int i=n-1; i>=0; i--){
    m-=v[i];
    usb+=1;
    if(m<=0)
      break;
  }

  cout<<usb<<endl;

  return 0;
}


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