n, b, p = map(int, input().split())
m = n - 1
t_b = m * (2*b + 1)
t_t = p*n
print(f'{t_b} {t_t}')
#include <bits/stdc++.h>
#include <iostream>
using namespace std;
int main() {
int n, b, p;
cin >> n >> b >> p;
cout << (n-1)*(b * 2 + 1) << " " << n*p ;
return 0;
}
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