659A - Round House - CodeForces Solution


implementation math *1000

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Python Code:

n,a,b=list(map(int,input().split()))
c=b%n
if c>=0:
	f=a+c
	if f>n:
		print(f-n)
	else:
		print(f)
else:
	d=n+b
	f=a+d
	if f>n:
		print(f-n)
	else:
		print(f)

C++ Code:

#include <bits/stdc++.h>

using namespace std;

int main()
{
    int n,a ,b;
    cin>>n>>a>>b;
    int k;
    if(b<0){
        while(b<0){
            b+=n;
        }
    }
    k = (a+b) % n;

    if(k==0) k = n;

    cout<<k<<endl;
    return 0;
}


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